Such ______the case, I couldn't help but______ him.A.being; supportB.is; to supportC.has b
Such ______the case, I couldn't help but______ him.
A.being; support
B.is; to support
C.has been; supporting
D.be; supported
Such ______the case, I couldn't help but______ him.
A.being; support
B.is; to support
C.has been; supporting
D.be; supported
【C9】
A.In any case
B.In case
C.In case of
D.In this case
A. switch(w ){case 1.0 : printf("*//n" ) ;case 2.0 : printf("**//n" ) ;}
B. switch(a ){case 1 printf("*//n" ) ;case 2 printf("**//n" ) ;}
C. switch(b ){case 1: printf("*//n" ) ;default : printf("//n" ) ;case 1+2:printf("**//n" ) ;}
D. switch(a+b ){case 1: printf("*//n" ) ;case 2:printf("**//n" ) ;default : printf("//n" ) ;}
A.in case
B.in the case
C.in case of
D.in the case of
设有程序段
switch(grade)
}case'A':printf("85----100\n");
case'B':printf("70----84\n");
case'C':printf("60----69\n");
case'D':printf("60\n");
default:printf("error!\n");
}
若grade 的值是'C',则输出结果是______。
【C11】
A.in view of
B.in case of
C.regardless of
D.in spite of
A. In case
B. In all cases
C. In a case
D. In any case
下列程序的运行结果是【 】。 include<stdio.h> void main() { int s=0,k; for(k=7;k>4;k--) { switch(k) { case 1: case 4: case 7:s++;break; case 2: case 3: case 6:break; case 0: case 5:s+=2;break;}} printf("s=%d" ,s);}