已知f1(t)=tε(t),f2(t)=ε(t)一ε(t一2),求y(t)=f1(t)*f2(t一1)*δ’(t一2)。
已知f1(t)=tε(t),f2(t)=ε(t)一ε(t一2),求y(t)=f1(t)*f2(t一1)*δ’(t一2)。
y(t)=f1(t)*f2(t一1)*δ’(t一2)=f1(t)*f2"(t一3)=tε(t)*[δ(t一3)一δ(t一5)]=(t一3)ε(t一3)一(t一5)ε(t一5)
y(t)=f1(t)*f2(t一1)*δ’(t一2)=f1(t)*f2"(t一3)=tε(t)*[δ(t一3)一δ(t一5)]=(t一3)ε(t一3)一(t一5)ε(t一5)