print(ls)()
A.'apple','orange','banana'
B.['apple','orange','banana']
C.[]
D.变量未定义的错误
C、[]
A.'apple','orange','banana'
B.['apple','orange','banana']
C.[]
D.变量未定义的错误
C、[]
A.ls–l|awk“{print$5}”
B.ls–l|awk‘{print$5}’
C.ls–l|awk{print$5}
D.ls–l|awk‘print$5’
A.橘子芒果草莓西瓜水蜜桃
B.橘子 芒果 草莓 西瓜 水蜜桃
C.西瓜
D.橘子芒果草莓西瓜水蜜桃
请写出下面程序的输出结果。
def fun(s,n):
If n==1:
return Is[0];
t=fun(s,n-1)
if t<ls[n-1]:
return t
else:
return Is[n-1]
print(fun([35,27,29,50-1],5)
print(fun([35,27,29,50-1],3))
运行以下程序,输出结果为()。s='a1b2c3d4' lst=[] n=len(s) for i in range(0,n,2): lst.append(s[i:i+2] ) print(lst[-3])
列表ls中存储了我国39所985高校所对应的学校类型。请以这个列表未数据变量,完善代码,统计输出各类型的数量。 ls = ["综合", "理工", "综合", "综合", "综合", "综合", "综合", "综合", "综合", "综合",\ "师范", "理工", "综合", "理工", "综合", "综合", "综合", "综合", "综合","理工",\ "理工", "理工", "理工", "师范", "综合", "农林", "理工", "综合", "理工", "理工",\ "理工", "综合", "理工", "综合", "综合", "理工", "农林", "民族", "军事"] d = {} for word in ls: d[word] = d.get(word,0)+1 for k in d: print("{}:{}".format(_________)
【C1】
A.tossed off
B.tossed about
C.tossed aside
D.tossed down
Apple addicts refer to people who ().
A.like Apple products
B.never use Apple products
C.work for Apple
D.know nothing about Apple
A.The Farmer and an Apple Tree.
B.How to Plant an Apple Tree.
C.A Friend's Gift.
D.An Apple Tree.