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[主观题]
设函数f(x),F(x)在[a,b]上连续,在(a,b)内可导,且F'(x)≠0,x∈(a,b).由于f(x),F(x)在[a,b]上都满足拉格朗
设函数f(x),F(x)在[a,b]上连续,在(a,b)内可导,且F'(x)≠0,x∈(a,b).由于f(x),F(x)在[a,b]上都满足拉格朗日中值定理的条件,故存在点ξ∈(a,b),使
f(b)-f(a)=f'(ξ)(b-a), (1)
F(b)-F(a)=F'(ξ)(b-a), (2)
又,F'(x)≠0,x∈(a,b),(1),(2)两式相除,即有
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以上证明柯西中值定理的方法对吗?
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