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[主观题]
设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=0.证明:存在ξ∈(0,1)使2ξf'(ξ)+f(ξ)=0.
设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=0.证明:存在ξ∈(0,1)使ξf'(ξ)+f(ξ)=0。
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设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=0.证明:存在ξ∈(0,1)使ξf'(ξ)+f(ξ)=0。
设f(x)在[0,1]上连续,在(0,1)内可导,且满足
证明至少存在一点ξ∈(0,1),使得f'(ξ)=(1-ξ-1)f(ξ)
设函数在f(x)上连续,在(0,1)试证至少存在一点ξ∈(0,1),使f'(ξ )=2ξ[f(1)-f(0)]
设f(x)在区间[0,1]上连续,在(0,1)内可导,且满足,试证存在一点ξ∈(0,1),使f(ξ)+ξf'(ξ)=0